Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(\frac{13}{19}+\frac{18}{19}+\frac{19}{19}=\left(\frac{13}{19}+\frac{17}{19}\right)+\frac{18}{19}=\frac{20}{19}+\frac{18}{19}=\frac{48}{19}\)
b) \(\frac{3}{5}+\frac{3}{16}+\frac{13}{16}=\left(\frac{3}{16}+\frac{13}{16}\right)+\frac{3}{5}=1+\frac{3}{5}=\frac{5}{5}+\frac{3}{5}=\frac{8}{5}\)
a) \(\frac{13}{19}+\frac{18}{19}+\frac{17}{19}\)
= \(\frac{31}{19}+\frac{17}{19}\)
= \(\frac{48}{19}.\)
b) \(\frac{3}{5}+\frac{3}{16}+\frac{13}{16}\)
= \(\frac{3}{5}+\left(\frac{3}{16}+\frac{13}{16}\right)\)
= \(\frac{3}{5}+\frac{16}{16}\)
= \(\frac{3}{5}+1\)
= \(\frac{3}{5}.\)
\(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.\frac{24}{25}.\frac{35}{36}\)
\(=\frac{3.2.4.3.5.4.6.5.7}{2.2.3.3.4.4.5.5.6.6}=\frac{7}{2.6}\)
\(=\frac{7}{12}\)
\(=\frac{1\cdot3\cdot2\cdot4\cdot3\cdot5\cdot4\cdot6\cdot5\cdot7}{2\cdot2\cdot3\cdot3\cdot4\cdot4\cdot5\cdot5\cdot6\cdot6}\)
\(=\frac{1\cdot7}{2\cdot6}\)
\(=\frac{7}{12}\)
12/14 + 15/20 + 6/7 + 3/4
= ( 12/14 + 6/7 ) + ( 15/20 + 3/4 )
= ( 6/7 + 6/7 ) + ( 3/4 + 3/4 )
= 12/7 + 6/4
= 48/28 + 42/28
= 90/28
= 45/14
Tham khảo nha !!!
6/4 x 45/10 + 105/10 : 2/3 - 3/2 x 5
= 3/2 x 45/10 + 105/10 x 3/2 - 3/2 x 5
= 3/2 x (45/10 + 105/10 - 5)
= 3/2 x 10
= 15
\(\frac{5}{6}:\frac{8}{9}-\frac{3}{4}:\frac{8}{9}\)
\(=\left(\frac{5}{6}-\frac{3}{4}\right):\frac{8}{9}\)
\(=\frac{1}{12}:\frac{8}{9}\)
\(=\frac{1}{12}\times\frac{9}{8}\)
\(=\frac{3}{32}\)
(\(\frac{5}{6}\)-\(\frac{3}{4}\)) : \(\frac{8}{9}\)
=\(\frac{1}{12}\): \(\frac{8}{9}\)
=\(\frac{3}{32}\)
k nhé, sau đó kb lun!
a) 18/15 + 7/15+12/15 = 18/15 + 12/15 +7/15
= 30/15+ 7/15
= 37/15
b) 9/7+8/7 + 11/7 = 9/7 + 11/7 + 8/7
= 20/7 + 8/7
= 28/7
a) \(\frac{18}{15}+\frac{7}{15}+\frac{12}{15}=\frac{18}{15}+\frac{12}{15}+\frac{7}{15}=\frac{30}{15}+\frac{7}{15}\)\(=\frac{37}{15}\)
b)\(\frac{9}{7}+\frac{8}{7}+\frac{11}{7}=\frac{9}{7}+\frac{11}{7}+\frac{8}{7}=\)\(\frac{20}{7}+\frac{8}{7}=\frac{28}{7}\)
a, \(\frac{6}{7}.\frac{16}{15}.\frac{7}{6}.\frac{21}{32}=\frac{6}{7}.\frac{7}{6}.\frac{16}{15}.\frac{21}{32}\)=\(1.\frac{16}{15}.\frac{21}{32}=\frac{7}{5.2}=\frac{7}{10}\)
Phần b T2
c,\(\frac{7}{4}.\frac{11}{21}+\frac{11}{21}.\frac{5}{4}=\frac{11}{21}.\left(\frac{7}{4}+\frac{5}{4}\right)\)=\(\frac{11}{21}.3=\frac{11}{7}\)
\(\) a) \(\frac37+\frac49+\frac{8}{14}+\frac{10}{18}\)
\(=\frac37+\frac49+\frac47+\frac59\)
\(=\left(\frac37+\frac47\right)+\left(\frac49+\frac59\right)\)
\(=1+1\) \(=2\)
b) \(\frac32+\frac34+\frac28+\frac{56}{16}\)
\(=\frac32+\frac34+\frac14+\frac72\)
\(\)\(=\left(\frac32+\frac72\right)+\left(\frac34+\frac14\right)\)
\(\)\(=5+1\) \(=6\)